Question

A force of 16.0 newtons is sufficient to set a box that is at rest into motion. If the coefficient of static friction is 0.380, what is the normal force acting on the box?

Answer 1

41

Answer 2

i get N < 42.1

for f > 16

Answer 3

thanks :)

Answer 4

can you tell me how you did that

Answer 5

the question says that the force sufficient to move it is 16 N

so that means that F - f = 0 --> F = f, is the force where there is no acceleration

F = f = 16 is given

f=μN
16=0.380N
N=42.1

I just realized that I misread the question actually, lol. Forget my < and > nonsense. Doesn't apply to this

Answer 6

but you had the right answer