Question

Solve the inequality: x^2 - 5x + 6 ≥ 0.
A. x ≤ 2 or x ≥ 3
B. 2 ≤ x ≤ 3
C. x ≤ or x ≥ 6
D. x ≤ -6 or x ≥ -1

Answer 1

(x-3)(x-2)= x^2-5x+6, do you need more help?

Answer 2

Yeah.

Answer 3

\[x ^{2}-5x+6>0,x ^{2}-5x>-6\]
adding both sides \[\left( \frac{ 5 }{ 2 } \right)^{2} i.e.,\frac{ 25 }{ 4 }\]
\[x ^{2}-5x+\frac{ 25 }{4 }>-6+\frac{ 25 }{4 }\]
\[\left( x-\frac{ 5 }{ 2 } \right)^{2}>\frac{ 1 }{ 4 },\left| x-\frac{ 5 }{2 } \right|>\frac{ 1 }{ 2 }\]
solve it.
\[(\left| x-a \right|>b means x-a <-b and x-a >b)\]

Answer 4

(x-3)(x-2)>=0 (its equal or greater than, but didn't know how to do the sign)
x-3>=0 and x-2>=0
just solve for x and see in which one it is right

Answer 5

Oh ok thank you!!

Answer 6

\[correction everywhere write \ge inplace of >\]