Question

integral of 4^(3x+1)

Answer 1

try u= 3x+1
du =...

Answer 2

\[\int\limits_{}^{}4^{3x+1}dx\]

Answer 3

i actually did ! but for some reason the 4 is throwing me off..
\[\frac{ 1 }{ 3 }\int\limits_{}^{}4^{u}du\]

Answer 4

integral of a^x is ... ?

there's a standard formula

Answer 5

\[\frac{ a ^{x} }{ \ln a }+ C\]

Answer 6

yes
here a = 4

Answer 7

mkay so my answer that i got is….\[\frac{ 4^{3x+1} }{ 3\ln 4 } + C\]

Answer 8

thats absolutely correct! :)

Answer 9

:O Yes! :)