Question

The area of a rectangle is 42 yd ^2 , and the length of the rectangle is 5 yd more than twice the width. Find the dimensions of the rectangle.

Answer 1

Hello Paullee I can help you with this. This is one of my favorite types of math problems

Answer 2

k thx appreciate it because I'm stuck

Answer 3

Just a sec, I am having problems with this one too lol, I know the answer is 12 and 3.5 but trying to get the work to be typed correctly

Answer 4

So, you have area = 42 and your length is 5 longer than 2widths
L*w=A
L+5=2w

(2w-5)w=42
2w^2-5w-42=0
(w-12)(w+7)=0, w has to be greater than 0
w=12
L*w=42
L*12=42
L=3.5

I think that is right :P

Answer 5

so: L=3.5 & W=12?

Answer 6

I think it should be the other way around actually O.O oh duh, the original second equation should be w+5=2L, sorry about that :P so just switch the two terms in everything

Answer 7

So L=12 & W=3.5

Answer 8

because this the example they gave me looking like this to fill in
Length:
Width:

Answer 9

Well 12 times 3.5 is 42, and and 12 is 5 more than double 3.5

Answer 10

thx

Answer 11

Np bro

Answer 12

it was right

Answer 13

your the best