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Factor and simplify :cot^4 + 2 cot^2 + 1
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Do you know how to factor quadratics?
Ax^2 + Bx + c =0
That is the form, can you factor it into a product of binomials?
like (cot^4x) + 1(cot^2x) ?
nvm that's grouping
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No, like x^2 +2x + 1 = (x + 1)(x+1)
yess
So, in this problem, cot^2x is like x in my factorization.
(cot^2 x +1)(cot^2 x +1)
Awesome!
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But that can still be simplified...
(cot^2 x)^2
Don't undo all your hard work! Do you recognize cot^2x + 1?
yess
:)
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yeah but the answers to choose from are Tan^4x CSC^2x sec^4x Csc^4x
and that equals csc^2x
One of them does, but we had 2.
so csc^4x
yup
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yayyyy
:)
These kind take practice. Keep at it!
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