e^0.3=2 Someone give me step by step please I get there are rules I don't know how to use them just talk me through it
There is something missing in the problem. Is there an x or some other variable somewhere?
oh yes im sorry e^0.3x=2 x is part of the exponent
e^(0.3x) = 2 To bring the x down from the exponent, you take natural logarithm on both sides. ln(e^(0.3x)) = ln(2) (0.3x) * ln(e) = ln(2) 0.3x * 1 = ln(2) x = ln(2) / 0.3 = ?
\[\Large \ln(A ^{n}) = n * \ln(A)\]
2.31?
yes.
awesome sauce!
alright. Do you have any questions about any of the steps or is it pretty clear?
take me through one more problem? maybe that will help?
ok. go ahead and post the problem.
3=log(2x-1) I got x+500.5 I'm just am not sure if this is right
I mean x=500.5
3=log(2x-1) or log(2x-1) = 3 means: 2x - 1 = 10^3 = 1000 2x = 1001 x = 500.5 yes, you have the correct answer.
thank you thank you
you are welcome. :)
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