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OpenStudy (anonymous):
algebra help
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jigglypuff314 (jigglypuff314):
like how in y = mx + b
b = y-intercept
in y= -4x^2 + 8x + 3
^ would be the y-intercept
jigglypuff314 (jigglypuff314):
vertex form... ... ... y = m(x-h)^2 + k
y = -x^2 + 2x + 5
= -(x^2 - 2x - 5)
= -(x^2 - 2x + 1 - 1 - 5)
= -(x^2 - 2x + 1) + 6
= -(x-1)^2 + 6
^ ^ so (1, 6)
jigglypuff314 (jigglypuff314):
crosses the x-axis at x = -6 and x= 2
because slope is 1/2 it is fat
jigglypuff314 (jigglypuff314):
slope is 1/2 therefore it is fatter
jigglypuff314 (jigglypuff314):
vertex is (3, 6)
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jigglypuff314 (jigglypuff314):
nope
vertex is (3, 6)
jigglypuff314 (jigglypuff314):
A would be correct :)
jigglypuff314 (jigglypuff314):
A
jigglypuff314 (jigglypuff314):
because vertex is (3, -6)
and plugged in point (0, 0)
jigglypuff314 (jigglypuff314):
f(x) = x^2 - 6x - 5
= x^2 - 6x + 9 - 9 - 5
= x^2 - 6x + 9 - 14
= (x - 3)^2 - 14
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jigglypuff314 (jigglypuff314):
-1/3 , 5
jigglypuff314 (jigglypuff314):
y = 12x^2 + 16x - 3 factor...
= (2x + 3) (6x - 1)
solve for each when 2x+3=0 and 6x-1=0
x = -2/3 and x = 1/6
jigglypuff314 (jigglypuff314):
no real solutions... so idk :/
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jigglypuff314 (jigglypuff314):
does not factor out evenly... so D
jigglypuff314 (jigglypuff314):
sure :)
jigglypuff314 (jigglypuff314):
k :)
jigglypuff314 (jigglypuff314):
I gtg :/ I'll be back later later maybe...
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