Starting at time t=0, an object moves along a straight line with velocity in m/s given by:

v(t) = 98-2t^2

where t is in seconds. When it momentarily stops,what is its acceleration?

Question

Starting at time t=0, an object moves along a straight line with velocity in m/s given by:

            v(t) = 98-2t^2     

where t is in seconds. When it momentarily stops,what is  its acceleration?

nincompoop · Answer

what is the initial velocity at t=0?

nincompoop · Answer

solve for t with that formula, which is typically in seconds
then obtain the derivative of it your formula
then plug the seconds in the derivative to solve for velocity

anonymous · Answer

@nincompoop  you mean like solving the equation first? , well , t = +/-7.

nincompoop · Answer

ya

anonymous · Answer

what should I do after this?

amoodarya · Answer

1. t=7 is correct 
2 . put t=7 in v'(t)=d/dt (v(t))=0-4t
so a(7)=-4(7) m/s^2

anonymous · Answer

Thank you @amoodarya