Question

can someone answer this for me !! what is the value of x? (A) 6 (B) 16/3 (C) 27 (D) sqaure root over 27 (E) 27/16 (F) square root over 324

Answer 1

what is the value of x?

Answer 2

using pythagora's theorem

Answer 3

find AC.

Answer 4

wads AC? did u get \[\sqrt{585}\] ?

Answer 5

no ..?

Answer 6

the answer choices are up there

Answer 7

\[\sqrt{27^2 -12^2} \] ?

Answer 8

i need to guide u because givin u the answer is against policy of open study

Answer 9

ok thats better

Answer 10

ok so using AC^2-(27-x)^2 = 12^2-x^2

Answer 11

can u find x now?

Answer 12

i dont understand how to do thaty ! :(

Answer 13

because by pythagora's theorem, AC^2-DC^2=AD^2=AB^2-BD^2 , which give u the above equation

Answer 14

As AC^2=585, x is 16/3

Answer 15

try to digest it

Answer 16

hm thank u