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Find all solutions to the equation. cos2x + 2 cos x + 1 = 0
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ambiguous!
Does cos2x mean \[\cos ^{2}x ?\]
Factor the left side.
cos2x = cosx^2 - sinx^2 and 1=sinx^2 + cosx^2. cancel the sinx^2 and you get 2cosx^2 + 2cosx = 0 set cosx = u and then factor it or use quadratic formula.
@melacho If you want help you MUST clarify: Is it cos(2x) or cos^2(x) ???
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and is there a domain?
@Mertsj cos^2x + 2 cos x + 1 = 0
Then factor the left side. It is like this: x^2+2x+1
notice is just a quadratic, thus you'd solve it like you'd any quadratic
I am so confused >.< I'm sorry
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(cosx + 1)^2 = 0 better?
cos(x)+1=0 cos(x)=1 x 3pi/2kpi
cos x = -1 x=pi + 2kpi
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