Question

The range of y = 2/3 sin x for π ≤ x ≤ 3pi/2 is _____.

-2/3 ≤ y ≤ 2/3
-2/3 ≤ y ≤ 0
0 ≤ y ≤ 2/3
2/3 ≤ y ≤ 1

Answer 1

whats the range of sin x ?
you know ?

Answer 2

yes it is -1≤ y ≤1

Answer 3

yes, so range of 2/3 sin x will be from -2/3≤ y ≤2/3

but there's an interval given.
so, plug the endpoints in your equation,
put x= pi in y = 2/3 sin x, find 'y1'
put x= 3pi/2 in y = 2/3 sin x, find 'y2'
and you will get the end-points of your range. [y1,y2]

Answer 4

how could i solve this in a graph form? or can i solve it in a graph form? because thats how im learning at school ):

Answer 5

2/3 sin pi = ... ?
2/3 sin 3p/2 = ... ?

Answer 6

2/3 sin pi= 0?

Answer 7

tbh i dont get what you have to plug in here ):

put x= pi in y = 2/3 sin x, find 'y1'
put x= 3pi/2 in y = 2/3 sin x, find 'y2'
and you will get the end-points of your range. [y1,y2]
what is x here?

Answer 8

you can graph cos x, right ?
just make the amplitude = 2/3
and see what values it takes from pi to 3pi/2

Answer 9

0 ≤ y ≤ 2/3 maybe??

Answer 10

when x= 3pi/2 , y = -2/3
so the range is actually -2/3 to 0

Answer 11

ohhhhhh! i got it
hope i remember this when im solving other problems :P

Answer 12

god luck! :)