Question

If F(x)=xcosx, what is the exact value of F′(0)?

Answer 1

F'(x)=cosx-sinx.x
F'(0)=1-0=0

Answer 2

first differentiate it.....
F(x)=xcosx
then
f'(x)=cosx-xsinx
then substitute f'(0)

Answer 3

F(x)=xcosx
F'(x)=x(-sinx)+cosx = -x sinx + cos x
F'(0)=-(0)( sin0) + cos 0
F'(0)= 0 + 1 = 1..............Answer

Answer 4

@blueskies7 Check it Ma'am.

Answer 5

thnaks!

Answer 6

*thanks