Question

Need help distributing f(x)=(x-3)(x-2)
and also
h(x)= (x-2i)(x+2i)

Answer 1

Think FOIL: First, Outer, Inner, Last.
For f(x):
First two terms: (x)*(x)=x^2
Outer two terms: (x)*(-2)= -2x
Inner two terms: (-3)*(x)= -3x
Last two terms: (-3)*(-2)= 6
Add them all up: x^2-2x-3x+6= x^2-5x+6

Same thing with h(x):=(x-2i)(x+2i)
F: (x)*(x)=x^2
O: (x)*(2i)=2ix
I: (-2i)*(x)=-2ix
L: (-2i)*(2i)=(-4)(i^2)
i is the square root of -1, so (-4)*(i^2)=4
Therefore h(x) := x^2+4

Answer 2

thank you so much :), I'm knew to this, needed help really bad. Do you mind if I ask another question?