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Let f be the function given by f(x)=x^3-3x^2. Find all values of c that satisfy the conclusion of the Mean Value Theorem of differential calculus on the closed interval [0, 3]. (Answer: 2) ( I know that f'(x)=3x^2-6x and f'(c)=3. But what to do next?)
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find the slope from 0 to 3, then set f'(x) = that slope, and solve for c
how to find that slope?
slope fomula
So the slope is 3?
Dear Idealist, Your interval is [0,3]. Evaluate the given function at both of those x values. If you like, graph the resulting points. Then, as sourwing suggests, use the slope formula to determine the slope of the line that connects these two points. Note that this is a "secant line."
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Before I answer that: Please type the two points that you've obtained.
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