*Integration* A ball is thrown vertically upward from a height of 6 feet with an initial velocity of 60 ft/sec. How high will the ball go? Use a(t) = -32 ft/sec^2 as the acceleration due to gravity and neglect air resistance. (I managed to get this down to the position function, s(t) = -16t^2 + 60t + 6. I just don't know how to get time using calculus!)

Question

anonymous · Answer

well, this is differentiation instead of integration

jaredstone4 · Answer

I think it /can/ be solved by differentiation, but this question is in a chapter on integration

anonymous · Answer

differentiation is required here. You can't solve this by integration

anonymous · Answer

you will have to set s'(t) = 0 to find the maximum height.

jaredstone4 · Answer

I was able to solve it thus far with integration, though. It's a "find the particular solution" type question...Integrating the acceleration function gets velocity and integrating velocity gets the position function. 
It must be a combination of differentiation and integration so I'll try what you said and let you know in a moment.

jaredstone4 · Answer

Yep it's good! Thanks so much!