Question

HELP trig

Answer 1

Find all solutions in the interval [0, 2π).

2 sin^2x = sin x

Answer 2

2sin^2x-sinx=0?

Answer 3

how

Answer 4

like can you show me

Answer 5

x = pi divided by three., two pi divided by three.

x = pi divided by two, three pi divided by two., pi divided by three., two pi divided by three.

x = 0, π, pi divided by six, five pi divided by six

x = pi divided by six, five pi divided by six

Answer 6

how does that get any of these answers

Answer 7

One more try!! factor sin out, what do you get

Answer 8

Don't forget this circumstance: you denied to study, not because I am not willing to help.
It's completely FINE, to me.
there you go: the answer:
x = 0, π, pi divided by six, five pi divided by six