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Deriving \(0!=1\) from the field axioms?
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Showing that \(b<a\) implies \(\prod_{i=a}^bx_i=1\) for all \(\{x_i\}\).
I think this is equivalent to the problem of showing $0!=1$ from field axioms.
I'm waiting for behavior to change before I jump in, here.
Nope, software problem. All I could see was gibberish. A little reboot and there seems to be some words, now.
@dan815 can you see the problem well? dan? can you help?
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