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Mathematics 21 Online
OpenStudy (anonymous):

A cars length is 4.70 meters and a caravans length is 6.78 meters, both correct to two decimal places. What would the upper bound of the cars length be?? Really don't understand this.

OpenStudy (anonymous):

Danndann@

OpenStudy (anonymous):

i dont no its really confusing me thats all the information i got on the question

OpenStudy (anonymous):

There is extra information given that you do not need to use. That is always confusing. If the questions first sentence was this: A cars length is 4.70 meters, correct to two decimal places. Than I think it is easier the answer: What would the upper bound of the cars length be?

OpenStudy (anonymous):

Is it suppost to be like an average or something?

OpenStudy (anonymous):

Nope, it is just about measurement errors. You do a calculation and find out that the car is 4.70 m. That is nice but in real life situations it might be important to know what errors you might have made. This question states that you are correct to two decimal places. Thus 4.70 is OK but it could be 4.7000001 or 4.709999999, we do not know. So the upper bound is 4.71

OpenStudy (anonymous):

Right okay thankyou x

OpenStudy (anonymous):

How about if i had to work out the upper bound for both the caravan and the car would it be12? or something along those lines?

OpenStudy (anonymous):

4.70+6.78=11.48 But if the upper bound is asked that would be: 4.71+6.79=11.50

OpenStudy (anonymous):

right thankyou

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