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OpenStudy (anonymous):
Is this a test question?
OpenStudy (anonymous):
no its for some hw
OpenStudy (anonymous):
In any Quadratic with three terms in the form of ax^2 + bx + c, take a * c.
Once you have foud this product, see what numbers would be factors of a*c, and yet add up to b. These could be negative too.
In your example, we will take 2 * 4 which is what?
OpenStudy (anonymous):
8
OpenStudy (anonymous):
oh i messed up its -4
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OpenStudy (anonymous):
Good, now what are some factors of 8 that when added together make 7?
OpenStudy (anonymous):
in the equation
OpenStudy (anonymous):
i have no idea
OpenStudy (anonymous):
ah! ok, so -8, so what are some factors of -8 that could add up to +7?
OpenStudy (anonymous):
OK, name some factors of -8.
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OpenStudy (anonymous):
4,2 and 8
OpenStudy (anonymous):
OK, so -2 and 4 multiplied = -8, when we add them together we get +2, so this is not the one we are looking for. Any other factors?
OpenStudy (anonymous):
1 and other than that i have no idea
OpenStudy (anonymous):
ok, 1 * -8 = -8 and 1 + -8 = -7...close! Could we somehow change the sign to make these work?
OpenStudy (anonymous):
im guessing we can but im not sure how
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OpenStudy (anonymous):
well if we tried -8 and +1, could we flip the signs?
OpenStudy (anonymous):
okay
OpenStudy (anonymous):
So if we tried -1 and +8, then -1 * 8 = -8 and -1 + 8 = +7... it works!
OpenStudy (anonymous):
okay yay ahh then what do i do
OpenStudy (anonymous):
You need to be able to try all the factors and all combinations of positive and negatives.
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OpenStudy (anonymous):
After that, you rewrite your original equation while using these two new numbers
OpenStudy (anonymous):
2x^2 -1x + 8x - 4
OpenStudy (anonymous):
Notice that we have not changed anything since -1x + 8x = 7x
OpenStudy (anonymous):
okay yeah
OpenStudy (anonymous):
from here, we will factor by grouping, so we will put parantheses around the first two terms, and then parantheses around the second two terms... (2x^2 - 1x) + (8x - 4)
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OpenStudy (anonymous):
Now look at the first group, do these terms have anything that can be pulled out?
OpenStudy (anonymous):
factor but not the x
OpenStudy (anonymous):
Well since they both share an x, we can pull an x out!
OpenStudy (anonymous):
oh i was looking at the second one okay
OpenStudy (anonymous):
So 2x^2 - 1x = x (2x - 1)
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OpenStudy (anonymous):
okay
OpenStudy (anonymous):
OK, now for the second group. Do they share anything?
OpenStudy (anonymous):
a common factor
OpenStudy (anonymous):
yes, what common factor?
OpenStudy (anonymous):
2 or 4
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OpenStudy (anonymous):
and
OpenStudy (anonymous):
perfect!
OpenStudy (anonymous):
4 is the largest common factor!
OpenStudy (anonymous):
okay
OpenStudy (anonymous):
so 8x - 4 = 4(2x - 1)
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OpenStudy (anonymous):
So now our equation 2x^2 + 7x - 4 = x(2x - 1) + 4(2x - 1)
OpenStudy (anonymous):
so now both terms have what in common?
OpenStudy (anonymous):
the 2x -1
OpenStudy (anonymous):
Excellent! So we factor that out and we get (2x - 1) (x + 4)
OpenStudy (anonymous):
Done!
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