Question

In the game of craps, the probability of a player winning with a natural (a roll of a 7 or 11 on the first roll) is:
(Remember, for each roll, you're rolling two dice, so "rolling a 7" means any combination of dice that adds to 7.)

Answer 1

some teach me how to do it.

Answer 2

*someone

Answer 3

alright there are 36 possible combinations, 6 sides on each dice, 6x6=36, now we need to find how many possibilities make 7 and 11.
for 7= 1+6, 5+2,3+4, 4+3, 2+5, 1+6 total of 6/36 so far ( there are repeat ones because of double dices)
and do the same for 11
then add up the # of combinations and divide by 36(total combos) to get the probability

Answer 4

I DO NOT EXPECT TO BE GIVEN AN ANSWER! JUST THE STEPS! IM FAMILIAR WITH THE TERMINOLOGY AND CONCEPTS TOO,

Answer 5

thats make sense! i was trying to find the prob of every possibility then add them up.

Answer 6

Alright,
1. Find # of total possibilities
2. Find possibilities of rolling a 7
3. Find possibilities of rolling a 11
4. Add up the possibilities of rolling a 7 & 11
5. Divide the possibilities of rolling a 7 & 11 by total possibilities

Answer 7

So there is that many, over 36.