The area under f(x) = 2x – 3 on the domain 3 ≤ x ≤ 7 is?
Do not tell me the answer, I know the answer. I just want to know how to do the problem.
integrate the function over the specified interval
\[\int\limits_{3}^{7}(2x-3)\,dx\]
i'm assuming you're in calculus. are you?
AP calculus :| Something I very much regret.
oh, come on now... you'll do great. do your best to keep a good attitude .
Lol, I try. Passed the first semester with a B-, so I'll manage somehow. Anyways, is there some type of formula to go by?
do you know how to integrate that?
Not exactly
okay, i'll help you with this and then i'll pass along some "cheat sheets" which will hopefully make your life a little better! ;) first off, we're gonna break this up because the function is a sum (or difference). \[\int\limits_{3}^{7}(2x-3)\,dx = \int\limits_{3}^{7}2x\,dx-\int\limits_{3}^{7}3\,dx = \left[\frac{2x^2}{2}-3x\right]_{3}^{7}\]
Then what happens...? Lol. I'm sorry, I'm very slow when it comes to math so please be patient with me.
evaluate at the points... \[(7^2-3(7))-(3^2-3(3))\]
(49 - 21) - (9 - 9) = 28
Thank you!!
check out this link. it's where i go the sheets from. http://tutorial.math.lamar.edu/Classes/CalcI/CalcI.aspx
These sheets will come in handy. Appreciate your help. :)
no worries!
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