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f(x)=x^2-x+3
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are you solving for x ?
finding difference quotient for each function and simplifying
Since the difference quotient is given by \(\dfrac{f(x+h)-f(x)}{h}\) and we're given \(f(x) = x^2-x+3\), we see that \(f(x+h)=(x+h)^2-(x+h)+3\). Therefore, we see that \(\dfrac{f(x+h)-f(x)}{h} = \dfrac{(x+h)^2-(x+h)+3 - (x^2-x+3)}{h}=\ldots\) To simplify this, you'll need to expand everything out and then simplify. Can you take things from here? :-)
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