Question

HELP PLEASE! I'll be your fan
Part 1. Create two radical equations, one that has an extraneous solution, and one that does not have an extraneous solution. Use the equation below as a model.

a√x+b+c=d

Use a constant in place of each variable a, b, c, and d. You can use positive and negative constants in your equation.

Part 2. Show your work in solving the equation. Include the work to check your solution and show that your solution is extraneous.

Part 3. Explain why the first equation has an extraneous solution and the second does not.

Answer 1

lol I suck at everything XD

Answer 2

@pgpilot326

Answer 3

@undeadknight26

Answer 4

@ehuman @SolomonZelman

Answer 5

thanks :)

Answer 6

Ok, for part a.


\[a√x+b+c=d\]

has solution:
\[2√x+5+7=4\]

has no extraneous solution.
\[2√x+5+7=11\]
(b/c 2√x=-1, √x=-.5 x=.25. if you plug it in, you will get a decimal for 2√x)

Answer 7

this is the answer to part 1 ? what about the a b c and d variables and constants or whatever

Answer 8

Yes yes, I used 2 5 7 and 4, as the constants that I plugged in for a b c and d.

Answer 9

thats it for part 1 ? thats exactly what i should submit ?

Answer 10

At frst you should understand, you should be able t do part 2 and 3, after you have art 1.

Answer 11

@SolomonZelman lol yea i wish i did understand

Answer 12

but ill try to do something, can you help me with another question ?

Answer 13

Will see how it goes, I am ding some other staff too.

Answer 14

ok, ill post it tag you and you get to it when you can or private message me, thanks !

Answer 15

lol I know this was a long time ago, but was this answer right??

Answer 16

@yeah_i_suck_at_math @SolomonZelman