Question

Find dy/dx if y=sin^2 x

Answer 1

\[\frac{ dy }{ dx }=\frac{ 1 }{ 2 }-\frac{ 1 }{ 2} \cos2x =\frac{ 1 }{ 2}x+\sin2x\]

Answer 2

That's because \[\cos2x=1-2\sin ^{2}x \] you get \[\sin^{2}x \] from this relation.

Answer 3

\[2 \sin(x)\cos(x)\]by the chain rule.