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Mathematics 21 Online
OpenStudy (anonymous):

This is a depiction of 2 forces acting on a puck (top view). Which direction would a 3rd force have to be to balance the forces? [picture below]

OpenStudy (anonymous):

OpenStudy (whpalmer4):

The 3rd force would have to have components the same magnitude as F1 and F2, but in the opposite direction. A little thought will (hopefully) tell you that the combination of F1 and F2 will produce a combined force going up and to the right, so F3 will have to be applied ...

OpenStudy (anonymous):

to the left ?

OpenStudy (whpalmer4):

to the left, and somewhat down, too...you have to cancel out the force going up (F1)

OpenStudy (whpalmer4):

|dw:1389304152529:dw| That's the combined F1+F2

OpenStudy (whpalmer4):

F3 will be equal in length to F1+F2, but in the opposite direction. I could also construct it by making two force vectors equal in length to F1 and F2, but again in the opposite directions, then combining those two

OpenStudy (whpalmer4):

|dw:1389304325318:dw| Not the best drawing, but hopefully you get the idea

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