Question

Can someone show me step by step how i do this?

Answer 1

solve by square roots

Answer 2

2r^2 - 32 = 0

Answer 3

Why don't you factor out the common factor of 2, to start?

Answer 4

Well it says i gotta use square roots?

Answer 5

Then move the number to the other side of the equals sign. Take the square root of both sides and you have your answer...

Answer 6

add 32 to the right side
2r^2=32
then divide both sides by 2
r^2=16
then square root both sides
r=4

Answer 7

did that help?

Answer 8

ooh! okay thank you(: yesss

Answer 9

I'll do a different problem as an example:
\[3x^2 -27 = 0\]Factor out the common factor:
\[3(x^2-9) = 0\]Divide both sides by 3
\[x^2-9 = 0\]Move 9 to right side by adding 9 to each side:
\[x^2-9+9 = 0 + 9\]\[x^2=9\]Take square root of each side:
\[x = \pm 3\]
Note that you get 2 answers, a positive one and a negative one

Answer 10

-4 is also an answer to the original problem!

\[2(-4)^2 = 32\]\[2(-4)(-4)=32\]\[2*16=32\]\[32=32\]

Answer 11

its + or - 4 ya sorry

Answer 12

yes i got it

Answer 13

thank you both(:

Answer 14

In general, if you're solving a problem and the highest term is \(x\), you'll have 1 answer. If it is \(x^2\), you'll have 2 answers. If it is \(x^3\), you'll have 3 answers. \(x^n\), \(n\) answers.

Answer 15

Sometimes the answers may be identical.

Answer 16

For example, \[x^2-2x+1=0\]has two solutions, but they are both \(x=1\).
\[x^2-1 = 0\]has two solutions, \(x=1\) and \(x=-1\)