Question

Write the equation 3x+4y-7=0 in normal form. I'll mark the answer I got but it doesn't look right to me.

3/5x+4/5y+7/5=0
-3/5x-4/5y-7/5=0
-3/5x-4/5y+7/5=0
3/5x+4/5y-7/5=0<--

Please explain what normal form is because I'm confused.

Answer 1

haha so am i.....@Loser66 what is normal form?

Answer 2

apparently it involves dividing by 5 ...

Answer 3

I become dummy with this question, :)

Answer 4

Yeah I don't know what to do here, I tried looking up normal form but I cant find anything that explains it....we're all stumped thats great....maybe my teacher miswrote the question. XD

Answer 5

most probably, normal = standard.

Answer 6

but isn't the original equation in standard?

Answer 7

yes, it is

Answer 8

to me, Yes

Answer 9

why only 5 is divided ??
\(\sqrt{3^3+4^2} =5\)

Answer 10

yes it is ... the only thing i would say is that if you make the line a vector then dividing by 5 makes it a unit vector

Answer 11

the answer you choose is the best one.
other choices can never be answer to this

Answer 12

i think your answer is right, dont change any of the signs

Answer 13

Hartnn I don't know, this is all the question states. Dumbcow, thats a good idea I'll see what I can do....although Im terrible with vectors XD

Answer 14

Okay, thats what I thought because changing the signs would mess up the original equation.

Answer 15

yes, good thinking :)

Answer 16

Oh I found the definition! Normal Form is x cos theta+y sin theta- p=0 Ugh more trig functions, I'm not even taking trig.

Answer 17

Ax+Bx+C=0 can be changed to Normal form by dividing the terms by +/-sqrtA^2+B^2 with the sign chosen to oppose the sign of C. Sooo...in this case...

3^3+4^2=25

sqrt25=5

3/5x+4/5y-7/5=0

So I was right I think...

Answer 18

nice!

Answer 19

Thanks for the help! and now you guys know too so you can help someone else now!

Answer 20

Exactly! thats the point of collaborative studying! :)
the very purpose of OpenStudy, learn and help :)