Probability and Statistics: The mean salary offered to students who are graduating from Coastal State University this year is $24,215, with a standard deviation of 3,712. A random sample of 80 Coastal State students graduating this year has been selected. What is the probability that the mean salary offer for these 80 students is $25,000 or more? Carry your intermediate computations to at least four decimal places. Round your answer to at least three decimal places.
@amoodarya ? help
you are given the population mean and the population std dev. First step: you need to find the sample mean (easy, it's the same as the population mean) and the sample std. dev.
Ok. I set it up like this: (25000-24215)/[3712/sqrt(80)]
I really suck at statistics so I'm probably doing this wrong
that gives a Z score. we need to use it to find the prob of getting 25,000 or more. which is the area to the right of that score.
ok don't go anywhere
can I use a Z table to figure it out?
yes.
wait. I'm doing something wrong. I got 1.8915 as a z-score... but isn't supposed to be 0.something?
that z-score means that 25,000 is 1.89 std dev above the mean |dw:1389462974566:dw|
Join our real-time social learning platform and learn together with your friends!