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Suppose that sina+sinb = sqrt(5/3) and cosa+cosb=1. What is cos(a-b)?
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Consider $$(\sin a+\sin b)^2=5/3,(\cos a+\cos b)^2=1$$ergo$$\sin^2a+\sin^2 b+2\sin a\sin b+\cos^2a+\cos^2b+2\cos a\cos b=5/3+1\\2+2(\sin a\sin b+\cos a\cos b)=5/3+1\\2(\sin a\sin b+\cos a\cos b)=2/3\\2\cos(a-b)=2/3\\\cos(a-b)=1/3$$
Woaahhh!! open my eyes!!! Thank you @oldrin.bataku
notice I used the fact that \(\sin^2a+\cos^2a=\sin^2b+\cos^2b=1\) and also the fact taht \(\cos(a-b)=\sin a\sin b+\cos a\cos b\)
mhmm, thank you!!!! =D
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