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Mathematics 23 Online
OpenStudy (anonymous):

let f(x)=sin(lnx) a.find two values of x satisfying f(x)=1 b.find two values of x satisfying f(x)=-1

OpenStudy (anonymous):

What is the ln(1) and ln(-1)?

OpenStudy (anonymous):

I don't know

OpenStudy (anonymous):

Do you have a calculator?

OpenStudy (anonymous):

yes

OpenStudy (anonymous):

OK ln references "natural log" you should have an ln button on your calculator. Push ln and enter 1. What do you get?

OpenStudy (anonymous):

@nelsonjedi I got 0

OpenStudy (anonymous):

So the sine(0) = ?

OpenStudy (anonymous):

0

OpenStudy (anonymous):

Right . Did you try ln(-1) ?

OpenStudy (anonymous):

yeah it said nonreal answer

OpenStudy (anonymous):

I did this all wrong..Let me take a look as I misread the question..Sorry

OpenStudy (anonymous):

ok

OpenStudy (anonymous):

f(x) =1 therefore 1 = sine (lnx). The arcsine of 1 = 1.507 thus 1.507 = (lnx).(this removes the sine) Expotiniate both sides by e (to remove the ln) and we get 1.507^e = x or 4.513 = x. You would do the same for -1.

OpenStudy (anonymous):

I see you required to have two answers so you would have to add 2pi to 1.507 for your second answer or 7.790 and solve as I did above. Does this help?

OpenStudy (anonymous):

yes it does, thanks!

OpenStudy (anonymous):

You are welcome. :-}

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