let f(x)=sin(lnx)
a.find two values of x satisfying f(x)=1
b.find two values of x satisfying f(x)=-1
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OpenStudy (anonymous):
What is the ln(1) and ln(-1)?
OpenStudy (anonymous):
I don't know
OpenStudy (anonymous):
Do you have a calculator?
OpenStudy (anonymous):
yes
OpenStudy (anonymous):
OK ln references "natural log" you should have an ln button on your calculator. Push ln and enter 1. What do you get?
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OpenStudy (anonymous):
@nelsonjedi I got 0
OpenStudy (anonymous):
So the sine(0) = ?
OpenStudy (anonymous):
0
OpenStudy (anonymous):
Right . Did you try ln(-1) ?
OpenStudy (anonymous):
yeah it said nonreal answer
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OpenStudy (anonymous):
I did this all wrong..Let me take a look as I misread the question..Sorry
OpenStudy (anonymous):
ok
OpenStudy (anonymous):
f(x) =1 therefore 1 = sine (lnx). The arcsine of 1 = 1.507 thus 1.507 = (lnx).(this removes the sine) Expotiniate both sides by e (to remove the ln) and we get 1.507^e = x or 4.513 = x. You would do the same for -1.
OpenStudy (anonymous):
I see you required to have two answers so you would have to add 2pi to 1.507 for your second answer or 7.790 and solve as I did above. Does this help?
OpenStudy (anonymous):
yes it does, thanks!
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