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If f(x) = x2 − 1, and f(2a) = 35, then what could be the value of a ? Answers; -6 -3 1 2 6 Can somebody explain please?
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\[f(x) = x^2-1\]That means to find the value of the function at any value of \(x\), we square \(x\) and subtract 1. If \(x = 2a\), we square \(2a\) and subtract 1: \[f(2a) = (2a)^2-1 = 4a^2-1\]Now, we know that \(f(2a)=35\)so we can find the value of \(a\): \[f(2a) = (2a)^2-1 = 4a^2-1=35\]\[4a^2-1+1=35+1\]\[4a^2=36\]\[a^2=9\]\[a=\pm3\]
Note that \(a=3\) would also be a valid answer, if it appeared in the list of answer choices.
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