Question

how do you convert 3r=cos(theta) to rectangular form??

Answer 1

do you know what a perfect square trinomial is?

Answer 2

no

Answer 3

well... then you may want to cover your perfect trinomials sections first,... since to make it rectangular, you'd need it -> http://www.youtube.com/watch?v=xGOQYTo9AKY

Answer 4

ok, I've been working on it for about 10 mins now, does the answer come out to

3x^2+3y^2-x=0????

Answer 5

yes

Answer 6

\(\bf 3r=cos(\theta)\quad \textit{multiply both sides by "r"}\\ \quad \\
3r^2=rcos(\theta)\implies 3(x^2+y^2)=x\implies 3x^2+3y^2-x=0\)

Answer 7

thanks a lot man

Answer 8

then you'd need to "completing the square" to get the actual equation, which is just a circle