Question

Three less than twice the third of three consecutive integers equals the sum of the three integers. Find the integers...... Where do i even start? 1+2+3=(3*2-3)?

Answer 1

Let the three consecutive integers be: N, N + 1, N + 2

"Three less than twice the third of three consecutive integers equals the sum of the three integers." 2(N+2) - 3 = N + N + 1 + N + 2

solve for N.

Answer 2

i see, thank you very much

Answer 3

You are welcome.
What are you getting for N?

Answer 4

i got -2

Answer 5

Yes, the three integers are: -2, -1 and 0.

Answer 6

hey, how would i simplify \[\sqrt{4-x^2}\]

Answer 7

a^2 - b^2 = (a+b)(a-b)
4 - x^2 = 2^2 - x^2 = (2+x)(2-x)

sqrt(4-x^2) = sqrt((2+x)(2-x))

Answer 8

thank you (:

Answer 9

can i jus take the twos out from there?