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Chemistry 23 Online
OpenStudy (anonymous):

Need help in checking my work: E = mcΔT 100 mL water = 100 g water q = (100 g)(1.00 cal/g degC)(15 degC) q = 1500 cal There are 1000 calories in 1 Calorie 1500 / 1000 = 1.50 Cal 1.50/1.850 x 1 Cal/1000 cal = 3.4

OpenStudy (anonymous):

This is the initial question: A gummie bear was tested through a flame-calorimeter test. The bear had a mass of 1.850 grams and the temperature of 100.0 milliliters of water increased by 15.0 degrees Celsius. How many Calories were in the gummie bear? Show all of your calculations.

OpenStudy (wolfe8):

Hmm I'm not sure if you have to divide it by the mass of the gummie bear since it asks for the Calorie in the whole thing. But other than that, I think you got it right.

OpenStudy (anonymous):

Thank you! Much appreciated.

OpenStudy (wolfe8):

You're welcome. I hope I'm right though :)

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