How do you write an equation in slope-intercept form for this problem?! (0,0); y=-3x+2
This is already in slope intercept from >.<
yea as fizi said, y = mx + b :) cheers
already in the form
@tHe_FiZiCx99 I realized that too but in my book it says "write an equation in slope-intercept form of the line that passes through the given point and is perpendicular to the graph of the given equation." So I think it means I need to substitute the x and y values but their both 0
Ohh ^^ well what're the "given points" and its perpendicular so its the reciprocal, so suppose 3/4x I'd be -4/3x
So would it be y=-1/3x+2 ?
what're the given points it says it gives you. You would plug in y - y1=m(x-x1)
The given points are (0,0)
Did I write the answer right? y=-1/3x
For example suppose it says, find the equation that is perpendicular to y = 3/4x + 6 and the given points are (-8,6) So the perp if 3/4 is -4/3x So, to find the equation with the new given points plug them into, y - y1=m(x-x1) So, y-6=-4/3(x-(-8)) -4/3 * 8/1 --> -4 * 8 = -32/3 Y-6 = -4/3x - 10.6 +6 +6 y = -4/3x -4.6
of*
Thanks! I got it now
Yw bo ;*
Join our real-time social learning platform and learn together with your friends!