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If N = 14 + 24 + 34 +................+ 784 . Find the remainder,when N is divided by 5
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start by cointing number of terms
*counting
nth term of an arithmetic series is: a + (n-1)d a = 14, d = 10, last term = 784. find n.
n=2/5
\(N=(4+\dots+4)+10\cdot(1+\dots+78)=4\cdot78+10\cdot(1+\dots+78)\)
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so \(N\equiv4\cdot78\equiv4\cdot8\equiv32\equiv2\pmod5\)
note \(4\cdot78\equiv4\cdot(70+8)\equiv4\cdot8\pmod{5}\) is the logic I used to jump from \(78\) to \(8\) there, sorry if that wasn't clear
understood @oldrin.bataku ,thanks to @ganeshie8 ,@ranga
np
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