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OpenStudy (anonymous):
Suppose that AD,BC,AC and BD are line segments with line AD parallel to line BC. If AD=3, BC=1, and the distance from AD to BC is 5, then what is the sum of the areas of the two triangles formed? TIA
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OpenStudy (anonymous):
|dw:1389869060773:dw|
OpenStudy (only4u):
its 0.5* (3+1) *5 .. unfold the side bc .. u will get a trapezium DACB
OpenStudy (anonymous):
The correct answer is 6.25. I just find it hard to go with the solution. Can someone help me in finding it? :3
OpenStudy (anonymous):
|dw:1389874309774:dw|
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