Suppose that AD,BC,AC and BD are line segments with line AD parallel to line BC. If AD=3, BC=1, and the distance from AD to BC is 5, then what is the sum of the areas of the two triangles formed? TIA

Question

anonymous · Answer

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only4u · Answer

its 0.5* (3+1) *5 .. unfold the side bc .. u will get a trapezium DACB

anonymous · Answer

The correct answer is 6.25. I just find it hard to go with the solution. Can someone help me in finding it? :3

anonymous · Answer

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