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If f(x) = tan(x), does the Mean Value Theorem apply on the interval [0,pi ] and why?
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@phi ???
Nope, because it is discontinuous at pi/2
You should look at the definition of when you can use the Mean Value Theorem
To use the Mean Value Thm you must have a function that satisfies both of the following: is continuous on the closed interval [a,b] <--- NOTICE is differentiable on the open interval (a,b). on the interval [0,pi ] what is the value of tan(pi) ?
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