Question

In the figure below, BD bisects ∠ABC. Which proportion is correct?




AB = AD
BC AC

AB = AD
BC DC

AB = DC
BC AC

AB = AD
BC BD

Answer 1

@jim_thompson5910

Answer 2

I want to say the second one is correct

Answer 3

why is that killem?

Answer 4

Using the rule found on this page

http://www.mathwarehouse.com/geometry/similar/triangles/angle-bisector-theorem.php


AB/AD = BC/CD


AB*CD = AD*BC


AB*CD/BC = AD


AB/BC = AD/CD


AB/BC = AD/DC


So the answer is choice B

Answer 5

In the figure below, BD bisects ∠ABC. What is the length of AD?



1.5 2.25
3.75 4

Answer 6

solve for x to get your answer

\[\Large \frac{5}{x} = \frac{3}{6-x}\]

Answer 7

This is using the same rule from that link I posted above.

Answer 8

ohh

Answer 9

And I should have pointed out that

AD = x
DC = 6-x


AD + DC = x + 6-x

AC = 6 (segment addition postulate)

Answer 10

gosh this is so confusing

Answer 11

\[\Large \frac{5}{x} = \frac{3}{6-x}\]

\[\Large 5(6-x) = 3x \ \text{ ... Cross Multiply}\]

\[\Large 30-5x = 3x\ \text{ ... Distribute}\]

\[\Large ...\]
\[\Large ...\]
\[\Large ...\]
\[\Large x = \ ??\]

Answer 12

x=3.75?

Answer 13

correct

Answer 14

jeesh for some reason at first i got like 7.5 so i had to redo it and check my work xD