Question

Solve 2x + y – z = 3
4x – y + 4z = 0
-3y + 2z = 6

Answer 1

x=2
y=−4
z=−3

Answer 2

step1. {2x+y-z=3}*2 since in 2nd equation x has co-efficient 4.
{4x-y+4z=0}*1
result will be
4x+2y-2z=6
4x-y+4z=0
step2. now subtract both equation both sides.
(4x+2y-2z)-(4x-y+4z)=6-0
=> 3y-6z=6---------let it be equation(1)
again
we have two equations
-3y+2z=6
3y-6z=6
add both the equetions both side
i.e. (-3y+2z)+(3y-6z)=6+6
=>-4z=12
=>z=-3
Now,
Put value of z in equattion 3y-6z=6 or -3y+2z=6
you'll get,
3y-6*(-3)=6
=>3y+18=6
=>3y=-12
=>y=-4
Now put values of z and y in any of your equetions given you'll get x.
:)

Answer 3

Thank you for your help