Question

If (a+3) divides evenly into ka^3−10a^2+2a+3 , find k

Answer 1

@Loser66

Answer 2

heeeeeeeeelp please @Loser66

Answer 3

let it =0, replace a = -3 to find k

Answer 4

k=10.3 ?

Answer 5

@Loser66

Answer 6

well is it??

Answer 7

@Loser66

Answer 8

I got k =-93/27

Answer 9

how?

Answer 10

I got +93/27

Answer 11

not (-)

Answer 12

ka^3-10a^2+2a+3 =0
ka^3 = 10a^2-2a-3
k = (10a^2-2a-3)/ a^3
replace a = -3
k = (10*(-3)^2-2(-3)-3)/ (-3)^3= 93/ (-27) = -93/27

Answer 13

Yes / No??

Answer 14

yes

Answer 15

ok

Answer 16

-93/27 = -31/9

Loser66 posted first.
Refer to the attachment.