Mathematics
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OpenStudy (anonymous):
Given the polynomial P(x)=3x^4−x^3−8x^2−4x
a. Is 3x + 2 a factor?
b. Find the remaining factors if (3x + 2) is a factor
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OpenStudy (anonymous):
@sourwing
OpenStudy (anonymous):
@Mertsj
OpenStudy (mertsj):
You have two choices:
1. Divide the polynomial by 3x+2 and see if the remainder is 0
2. Factor the polynomial.
OpenStudy (mertsj):
What is your pleasure, my dear?
OpenStudy (anonymous):
divide @Mertsj
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OpenStudy (mertsj):
Did you do it?
OpenStudy (anonymous):
Im not sure how to
OpenStudy (mertsj):
I can't show you because the draw function isn't working.
OpenStudy (anonymous):
can you type it?
OpenStudy (mertsj):
First factor out the x
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OpenStudy (anonymous):
ok I did @Mertsj
OpenStudy (mertsj):
Did you get:
x(3x^3-x^2-8x-4)
OpenStudy (anonymous):
yeah
OpenStudy (mertsj):
So if 3x+2 is a factor then (3x+2)( )=3x^3-x^2-8x-4
OpenStudy (anonymous):
wait what? theres a blank in the middle
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OpenStudy (mertsj):
I know. That would be the answer to the long division problem. It would have to start with x^2 and end with -2
OpenStudy (anonymous):
can you show it to me ?
OpenStudy (mertsj):
(3x+2)( x^2 -2 )=3x^3-x^2-8x-4
OpenStudy (mertsj):
I can try.
OpenStudy (anonymous):
ok
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OpenStudy (mertsj):
___x^2_-x___-2_________________________
3x+2| 3x^3-x^2-8x-4
3x^3+2x^2
-3x^2-8x
-3x^2-2x
-6x-4
-6x-4
OpenStudy (anonymous):
why are there lines?
OpenStudy (anonymous):
ok nvm I know why
OpenStudy (anonymous):
ok so what do I do now?
OpenStudy (mertsj):
Because it is a long division problem
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OpenStudy (mertsj):
Answer the questions.
Is 3x+2 a factor?
OpenStudy (anonymous):
no
OpenStudy (anonymous):
its no right?
OpenStudy (mertsj):
Why do you say no?
OpenStudy (anonymous):
because its not in the answer at the top in long division ?
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OpenStudy (mertsj):
What is the answer to the long division problem?
OpenStudy (anonymous):
x^2-x-2
OpenStudy (mertsj):
What is the remainder?
OpenStudy (anonymous):
0
OpenStudy (mertsj):
Is 4 a factor of 12?
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OpenStudy (anonymous):
yes
OpenStudy (mertsj):
Yes it is because 12 /4 is 3 and the remainder is 0
OpenStudy (mertsj):
So use that same reasoning. Is 3x+2 a factor of your polynomial?
OpenStudy (anonymous):
yes cause the remainder is 0
OpenStudy (anonymous):
right?
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OpenStudy (mertsj):
Yes so now we know that your polynomial is equal to :
x(3x+2)(x^2-x-2)
OpenStudy (anonymous):
so how can I find the remaining factors for part b ?
OpenStudy (mertsj):
So now do the second part which is to complete the factoring.
OpenStudy (mertsj):
You surely know how to factor a trinomial.
x^2-x-2
OpenStudy (anonymous):
factoring of the polynomial right ?
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OpenStudy (anonymous):
3x^3-x^2-8x-4
OpenStudy (mertsj):
3x^3-x^2-8x-4=x(3x+2)(x^2-x-2)
OpenStudy (mertsj):
We know those are the factors but the third factor can be factored again. That is your job now...to factor x^2-x-2
OpenStudy (anonymous):
thanks @Mertsj
OpenStudy (mertsj):
did you get it finished?
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OpenStudy (anonymous):
yes
OpenStudy (mertsj):
Good for you!!
OpenStudy (anonymous):
I got (x+1) (x-2)
OpenStudy (mertsj):
yes
So
3x^4--x^3-8x^2-4x=x(3x+2)(x+1)(x-2)
OpenStudy (mertsj):
And that is what you should write on your paper.
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OpenStudy (anonymous):
thanks so much!
OpenStudy (mertsj):
yw