Question

Two charged smoke particles exert a force of 3.0E-5 N on each other. What will be the force if they are moved so they are 1/4.0 as far apart?

How would I do this

Answer 1

would it be 1.88E-6

Answer 2

I have not memorized the equation, but i believe the force is inversely proportional to the square of the distance. Since they have been moved closer by 1/4 squaring to 1/16, so the force would be 16 times what it was at the original distance.

Answer 3

so do i divide it by 16 or multiply it

Answer 4

Please re-read my post, it tells you that it would be greater by 16 TIMES

Answer 5

sorry, so would it be 4.80 E-4

Answer 6

could u also help with another question ?

Answer 7

If I can, I am not to good at these abstract, theoretical problems.

Answer 8

I think ur better than me.....A person scuffing her feet on a wool rug on a dry day accumulates a net charge of - 75.0 µC. How many excess electrons does this person get?

Answer 9

or this one A charged water droplet of radius 0.027 mm remains stationary in the air, as the electric force on it just balances the gravitational force. If the electric field of the Earth is 150 N/C, how many excess electron charges must the water droplet have?

Answer 10

would the answer for the first one be 4.68E14

Answer 11

I would need to know how many electrons equal a coulomb. then take .75 10^-6 times that. The charged water droplet I don't want to mess with it.......too unfamiliar with that.

Answer 12

good luck with these.

Answer 13

1.602E-19