Question

Write the equation of the line that passes through( -4,3)and is perpendicular to the line y=7/5x-3/5

Answer 1

Two perpendicular lines have slopes which are "flipped" and have different signs. For example, lets say a line had a slope of (3/2). A perpendicular line would have a slope of (-2/3)

Answer 2

Other than that, you do the same thing as before.

Is the equation y=7/((5x-3)/5) (Does it have a complex fraction?

Answer 3

Is this the equation? You don't use ( or ) so I want to make sure

Answer 4

Or is this the equation:

Answer 5

Can you draw out the equation as it appears? I can't help you, since the two equations are very different from each other

Answer 6

*unless I know which one it is

Answer 7

A.5x+7y=1
B.7x+5y=-13
C.7x+5y=-1
D.3x+5y=7

Answer 8

I keep getting the wrong answer because I am going off the equation

y = (7/5)x -(3/5)

Answer 9

@superdavesuper

Answer 10

So have a line that is perpendicular the slopes have to be opposite
So the slope of the other equation for be (-5/7)
Now that we know that we start with
y-y1=m(x-x1)
Plug in what we know ( -4,3) ((remember (x,y)), and m=(-5/7)
So
y-(3)=(-5/7)(x+4)
y-3=-5/7x-23/7
Add 3 to both sides
y=-5/7x-3/7
Multiply both sides by 7
7y=-5x-3
Add 5x to both sides
5x+7y=-3
This is what I got

Answer 11

y = 7/5 x -3/5
perpendicular line so slope is -1/m =-5/7
point on line (-4,3)
3 = -5/7 (-4) + b
b = 1/7
eqn y = -5/7 x + 1/7
multiply by 7 to get rid of fraction rewrite to match format of answer
7y +5x = 1

Answer 12

rosedryer had the right idea but this line y-(3)=(-5/7)(x+4) had an error
x = -4 need to find b