Question

Given: The equation of a line y= -5x+2.

Part a. Write the equation of the line in slope-intercept form parallel to the given line that contains the point (3, -7)

Part b. Write the equation of a line in slope-intercept form perpendicular to the given line that contains the point (10, -7).

Answer 1

Slope of the original line: -5.
a)The lines are parallel, so the slopes are the same. Form the equation:
y-y1 = -5(x-x1)

Answer 2

y - (-7) = -5(x-3). Simplify.

Answer 3

y=-5x+22?

Answer 4

slope is -5. Parallel line will have same slope.
y = mx + b
slope(m) = -5
(3,-7) x = 3 and y = -7
now we sub and solve for b
-7 = -5(3) + b
-7 = -15 + b
-7 + 15 = b
8 = b
your parallel equation is : y = -5x + 8
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slope is -5. Perpendicular line will have negative reciprocal slope. All that means is " flip " the slope and change the sign. Negative reciprocal of -5, or -5/1, is 1/5.
y = mx + b
slope(m) = 1/5
(10,-7) x = 10 and y = -7
now we sub
-7 = 1/5(10) + b
-7 = 2 + b
-7 - 2 = b
-9 = b
perpendicular equation is : y = 1/5x - 9
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any questions ?

Answer 5

Nope, thank you :)