4x cos x (a) lim x→0 f(x) = (b) lim x→π/3 f(x
do you know much about limits @shorouq91
i gont part a but i dont know who to do part b
ok, what was your answer to part a, just to be sure
0
part b 4*pi/3 cos(1/2)
u were almost there. AS cos x approches \[\frac{ \pi}{ 3 }\], it becomes half. Not \[\cos \frac{ 1 }{ 2 }\]
so, u can write the solution as\[4\frac{ \pi }{ 3} (\frac{ 1 }{ 2 }= \frac{ 2\pi }{ 3 }\]
i dont under stand it
sorry i forgot to close the parenthesis . ok, let's start\[4xcosx =(\lim_{x \rightarrow \frac{ \pi }{ 3}}4x) ( \lim_{x \rightarrow \frac{ \pi }{ 3}}cosx)\]
do you understand that part
@shorouq91
not much
the limit of 4x multiplied by the limit of cosx, we will deal with the limits in two parts, 4x, and cosx, and instead of x, we plug in pi/3 like u did, such that u will have\[4\frac{ \pi }{ 3}\] on the first part. on the second part - QUESTION IS, WHAT IS PI/3 IN DEGREES, DO U KNOW?
@shorouq91 , what z pi/3?
in degrees?
1/2
pi = 180 degrees, divide that by three, u will get 60 degrees, so, as x approaches 60 degrees, what what is cos 60?
1/2
so, the second part which is cosx, as x approaches pi/3, it becomes half!, now we have:\[(4\frac{ \pi }{ 3})(\frac{ 1 }{ 2 }) = \frac{ 2\pi }{ 3 },\] which is the solution to your second part!
i dont know
im stock in the last part
if we are to find the limit, as x approaches pi/3, of a function like the one above, that has two parts, 4x and cosx, we plug in pi/3 in seperately, and multiply the limits when we find them, so the limit for 4x was, as x approaches pi/3= 4(pi/3) [ instead of x, we put in the limit. and the second part, also, as x approaches pi/3, which is 60 degrees, it becomes cos 60=1/2 then 4(pi/3) x 1/2 [remember it was 4x times cosx!
4(pi/3) x 1/2 = 2pi/3
oky got it thank you so muchh i took to much time
always a pleasure. But did you get the trick here? You plug in the limit, but then, u must know that cos pi/3 = 1/2!
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