Question

AM I RIGHT??
see attachment below:

Answer 1

@Loser66 @ikram002p

Answer 2

I don't know, I don't get the second part you do from AB*m1 and AB*m2
to me, your AB is perfect. And stop at there ( the first column)

Answer 3

oh because the lines are skew, so i assume that vector AB is perpendicular to the given lines

Answer 4

to solve for s, and t,
direction of L1 = (1,-1,1)
direction of L2 =(2,1,0)
cross them to get the vector which perpendicular to both L1 and L2 , which is (-1,-2,3)
then make AB = (...............) =(-1,-2,3) to solve for s, and t, I get s = -1, t =2
plug back to get A, B

Answer 5

since i am looking for the minimal distance
the minimal distance from the lines is the length of the line perpendicular to them

Answer 6

does it make sense to you?

Answer 7

i guess so ,
m1 and m2 are the direction vectors
hbu? does my solution make sense to you? O.o

lol, i guess not, maybe i'll ask my teacher tomorrow
thanks:)

Answer 8

ok, let do so, heheheh... Sorry for being helpless

Answer 9

helpless?? are you kidding meh? you ALWAYS help me (^_^)

Answer 10

ty