Question

The deer population increases at a rate of 3% per year. There are 1253 deer this year. Write a function that models the deer population. About how many deer will there be in 6 years
9134

1044

1496

1777




An investment of $200 increases at a rate of 9.5% per year. What is the growth factor, b

0.095

1.095

1.95

9.5

Answer 1

Assume that both of problems follow exponential growth/decay rule with general function is:

\[y = y(0) e^{kt}\]
with k is growth/decay constant rate.

(1) Deer population function
y(0) = 1253
k = 3%
t = 6 (years)

So y(6) = 1253 . e^(0.03*6) ~ 1500 (deers)

The answer is approximated, so the most close correct option is C: 1496 deers

(2) Growth factor b is rate 9.5% = 0.095 (A)

Answer 2

thank you