Medal+Fan if answered with explanation on how to do this thanks! Please! Help me!
3x+8y=12 2x+2y=3 1: Create an equivalent system of equations by replacing one equation with the sum of that equation and a multiple of the other. Show the steps to do this. 2: Show that the equivalent system has the same solution as the original system of equations.
@ml1042903 could you please help me? my friend said you were good and very helpful
hold up it might take a sec.
thats okay.
Sorry can't help. Try these websites: https://www.khanacademy.org/math/cc-eighth-grade-math/cc-8th-systems-topic/cc-8th-systems-with-substitution/v/solving-systems-by-substitution-1 http://www.regentsprep.org/Regents/math/ALGEBRA/AE3/AlgSys.htm Still trying though.
Thanks..
@DE3100
This would be very easy if the drawing tool was working D: even though I'm a lousy artist
I can do it step by step but it'll look messy lol Cx
Its fine.
So pick one equation and multiply it by a scalar. Can you do that?
I'll take the first equation, I'll multiply every term by -2 to make the x's the same. 3x(-2)+8y(-2)=12(-2) The new equation is -6x -16y = -24 For the other I'll multiply it by 3, 2x(3)+2y(3)=3(3) 6x +6y = 9 _________________________________________________ New equation: {-6x -16y = -24 { 6x +6y = 9 See that the x's cancel out? Add them up, -10y = -15 -10y = -15 /-10 /-10 y = 1.5 Plug in y (1.5) to solve for x, 6x +6(1.5) = 9 6x + 9 = 9 -9 -9 6x = 0 /6 /6 x = 0 So check my plugging in, 6(0) + 6(1.5) = 9 0 + 9 = 9 9 = 9 <-- this is true Now try this on the original equation, your pair is (0,1.5) 3(0)+8(1.5)=12 0 + 12 = 12 12 = 12 <-- true
By plugging in (0,1.5) into one of the equation it should give you a true statement :3
Thank you so much!!!!
You welcome :*
Yea thanks @tHe_FiZiCx99 she really needed the help :)
>.< k
Join our real-time social learning platform and learn together with your friends!