Question

Indicate the equation of the given line in standard form.

The line through point (-3, 4) and perpendicular to a line that has slope 2/5

Answer 1

Okay, if you have any equation of a line

Answer 2

okay I cant draw

Answer 3

Any equation of a line
y=2x/5 +3
the gradient (slope) is 2/5

if you have a line perpendicular to this line, the slope is -1/m
in this case, m is 2/5
solve to work out your new gradient

the equation of a line is
y-y1=m(x-x1)

where y1 is the y coordinate, x1 is the x coordinate

Answer 4

i know but i dont get how to solve it ???

Answer 5

okay so your perpendicular slope is -1/(2/5)
which gives -5/2
so m=-5/2

y-y1=m(x-x1)

substitute the coordinate values into y1and x1, where y1 is y coordinate, x1 is x coordinate

so

y-4=-5/2(x+3)

simplify, get into form y=mx+c

Answer 6

They want the answer in standard form. So rearrange it to look like: Ax + By = C

Answer 7

so 4x+-5=3

Answer 8

is that right?

Answer 9

y-4=-5/2(x+3)

multiply by 2
2y-8=-5(x+3)
expand the bracket
2y-8=-5x-15
2y+5x=-7

Answer 10

Oh! lol i had the eqaution all backwards oops , but hey thanks @amorfide

Answer 11

:)